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Theory of Indices: Laws, Rules & Formulae | B.Com Notes

Study material and explanations for Unit 1

Theory of Indices: Laws, Rules & Formulae

1. Meaning of Base and Index

If a is any real number and n is a positive integer, the repeated product:

a × a × a × … (up to n times) = aⁿ

Here:

  • a is called the Base
  • n is called the Index, Exponent, or Power

2. Fundamental Laws of Indices

The syllabus requires preliminary knowledge of index formulae. These six foundational algebraic laws govern all exponential expressions:

The Six Fundamental Laws of Indices
1. Product Law
When bases are identical, powers are added:
aᵐ × aⁿ = aᵐ⁺ⁿ

Example: 2³ × 2⁴ = 2³⁺⁴ = 2⁷ = 128
2. Quotient Law
When dividing identical bases, powers are subtracted:
aᵐ ÷ aⁿ = aᵐ⁻ⁿ  (a ≠ 0)

Example: 5⁶ ÷ 5² = 5⁶⁻² = 5⁴ = 625
3. Power of a Power Law
Powers are multiplied when raised to another power:
(aᵐ)ⁿ = aᵐˣⁿ

Example: (3²)³ = 3²ˣ³ = 3⁶ = 729
4. Zero Index Rule
Any non-zero quantity raised to power zero equals 1:
a⁰ = 1  (a ≠ 0)

Proof: aᵐ ÷ aᵐ = aᵐ⁻ᵐ = a⁰ = 1
5. Negative Index Rule
A negative exponent indicates the reciprocal:
a⁻ⁿ = 1 / aⁿ  (a ≠ 0)

Example: 2⁻³ = 1 / 2³ = 1 / 8
6. Fractional Index Rule
A fractional exponent represents a radical root:
aᵐ/ⁿ = ⁿ√(aᵐ) = (ⁿ√a)ᵐ

Example: 27^(2/3) = (³√27)² = 3² = 9

3. Step-by-Step Practice Simplifications

Problem 1: Simplifying an Index Expression

Question: Simplify the algebraic fraction:

E = [ 2^(n+4) - (2 × 2^n) ] ÷ [ 2 × 2^(n+3) ]

Step-by-Step Solution:

  1. Expand using the product rule [ 2^(n+k) = 2^n × 2^k ]:
    • In the numerator: 2^(n+4) = 2^n × 2^4 = 16 × 2^n
    • Second term: 2 × 2^n = 2^1 × 2^n = 2 × 2^n
    • Numerator becomes: (16 × 2^n) - (2 × 2^n) = (16 - 2) × 2^n = 14 × 2^n
  2. Expand the denominator:
    • 2 × 2^(n+3) = 2^1 × 2^n × 2^3 = 2^n × (2 × 8) = 16 × 2^n
  3. Cancel the common term 2^n from both numerator and denominator:
    • E = (14 × 2^n) ÷ (16 × 2^n)
    • E = 14 ÷ 16
  4. Reduce the fraction:
    • Divide numerator and denominator by 2:
    • E = 7 / 8 (or 0.875)

Problem 2: Solving an Exponential Equation for x

Question: Solve for x:

9^(x+2) = 240 + 9^x

Step-by-Step Solution:

  1. Rewrite 9^(x+2) as 9^x × 9²:
    • Since 9² = 81, 9^(x+2) = 81 × 9^x
  2. Substitute into the equation:
    • 81 × 9^x = 240 + 9^x
  3. Transpose 9^x to the left-hand side:
    • (81 × 9^x) - (1 × 9^x) = 240
    • 80 × 9^x = 240
  4. Divide both sides by 80:
    • 9^x = 240 ÷ 80 = 3
  5. Convert both sides to a common base (Base 3):
    • Since 9 = 3², we have (3²)^x = 3¹
    • 3^(2x) = 3¹
  6. Equate the powers (since the bases are identical):
    • 2x = 1
    • x = 1 / 2 (or 0.5)